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C Program to find the count of even and odd elements in the array

Last updated on September 23, 2020

The following is a C program to count even and odd elements in the array:

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/***************************************************************
 Program to find the count of even or odd elements in the array
 ***************************************************************/

#include<stdio.h> // include stdio.h library
#define MAX 5

int main(void)
{    
    int arr[MAX] = {1, 5, 9, 14, 200};
    int even_count = 0, odd_count = 0;   // variables to store even or odd count

    // iterate over the arrays
    for(int i = 0; i < MAX; i++)
    {
        // check for even number
        if(arr[i] % 2 == 0)
        {
            even_count++;
        }

        else
        {
            odd_count++;
        }
    }

    printf("Even elements = %d\n", even_count);
    printf("Odd elements = %d", odd_count);

    return 0; // return 0 to operating system
}

Try it now

Expected Output:

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2
Even elements = 2
Odd elements = 3

How it works #

  • In line 10, we declare and initialize an array named arr.
  • In line 11, we declare and initialize variables even_count and odd_count, to store the count of even and odd elements respectively.
  • In line 14-27, we have for loop to iterate over the items in the array.
  • In line 17, we have an if statement to check for even number. If the condition evaluates to true, we increment the even_count by 1. Otherwise, the element is odd and we increment the odd_count by 1. The for loop terminates when we run out of elements in the array.
  • In lines 28 and 29, we print the value of even_count and odd_count using the print statement.

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